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Tan ⁡ ( α − β) = tan ⁡ ( α) − tan ⁡ ( β) 1 tan ⁡ ( α) tan ⁡ ( β) \tan (\alpha \beta) = \dfrac {\tan (\alpha) \tan (\beta)} {1 \tan (\alpha) \tan (\beta)} tan(α−β)= 1tan(α)tan(β)tan(α)−tan(β) By the way, in the above identities, the angles are denoted by Greek lettersTan( a b) is equal to P and tan(ab) equal to Q then find tan 2aA = b * tan(α) b = a * tan(β) Given area and one leg; If Tan A B X And Tan A B Y Find The Values Of Tan2a And Tan2b Trigonometric Ratios Of Compound Angles Trigonometry Sci Pi Tan a b formula

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